Wednesday, November 08, 2006
Lebesgue v. Riemann integration analogy
One of my (favorite) instructors compared Lebesgue integration to Riemann integration with the following analogy:
Say you dump your change jar on the floor. Riemann goes along and adds up each coin as he picks it up; whereas Lebesgue counts the number of pennies, nickels, dimes, quarters, etc. and multiplies each total by its corresponding value.
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Say you dump your change jar on the floor. Riemann goes along and adds up each coin as he picks it up; whereas Lebesgue counts the number of pennies, nickels, dimes, quarters, etc. and multiplies each total by its corresponding value.
Labels: mathematics